How to know if one journal is a SSCI or SCI journal?

Friday, April 27, 2012

SCI stands for science citation index, and SSCI stands for social science citation index. I personally do not think SCI and SSCI are very important in American academia; however, in some countries, such as Taiwan and China, SSCI and SCI are used to rank universities. In this situation, knowing your target journal is SCI or SSCI journal is critical.

A couple ways to achieve this goal.

1) Check out at SCI and SSCI official site (recommendation: 4 out of 5)


SCI: http://science.thomsonreuters.com/cgi-bin/jrnlst/jloptions.cgi?PC=D
SSCI: http://www.thomsonscientific.com/cgi-bin/jrnlst/jloptions.cgi?PC=J

Take SSCI site for example. If I want to know if Foreign Language Annals is a SSCI journal, simply typing foreign in the search box.
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Hit search and you will see the results. Voila, it is a SSCI journal.
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The second approach (recommendation: 5 out of 5) is to use the following site:

http://publik.tuwien.ac.at/info/sci_search.php?lang=2

This site is self-explanatory, and I do not see the need to do any screen capturing. 


The third approach is to use Web of Science (recommendation: 3 out of 5), but it requires annual subscription. Please check your library and see if they subscribe it.


http://apps.isiknowledge.com/WOS_GeneralSearch_input.do?product=WOS&search_mode=GeneralSearch&preferencesSaved=

Select  publication name and type foreign l*.3.png

Click analyze result.
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It will shoe fields that you can analyze. Since we are looking for the journal, please choose source title ad click analyze.
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The fourth approach is to use Journal Citation Report, but this one also require library subscription (recommendation: 4 out of 5).


http://admin-apps.isiknowledge.com/JCR/JCR

Stata: Count groups by individuals

Wednesday, April 25, 2012

One friend asked me the following question:

How can I transform the following format into:

id level
1 A
1 A
1 B
2 A
2 B
3 B






this one?

id level #ofA #ofB
1 A 2 1
1 A 2 1
1 B 2 1
2 A 1 1
2 B 1 1
3 B 0 1

Well, I do not think there is one command for this task. This is not very difficult if there are only two groups to count.

The way I achieve this task is:

use "http://images.researcher20.com/stata_group/stata_group.dta", clear
egen acount = group(level)
gsort +id +acount
by id: egen acount2 = count(acount) if acount==1
bys id: replace acount2 = acount2[_n-1] if acount2==.
replace acount2=0 if acount2==.
bys id: egen bcount2 = count(acount) if acount==2
gsort +id -level
by id: replace bcount2 = bcount2[_n-1] if bcount2==.
replace bcount2=0 if bcount2==. 


Level variable is a string variable, so I use egen to get a group id. If you are interested in learning more details, you can check my previous post:Stata: Create id by group.

After creating a new group id, I sort id and level. How do I count how many As and Bs? I count # of As using egen, but  you may notice that if the value is B, # of A would be missing. So my next step is to fill up this missing with the value of previous record. This is why I sorted data at the beginning.

If there is no A, then replace the value from missing to zero.

The way I count # of Bs is similar. The only difference is sorting.

You may be curious: how about if I have more than three groups? Well, my code only works for two groups, and I have not found a way to count three groups by individuals.

If you have tips or code to achieve the task, please let me know!

Update
2012.4.27:

One friend shared with me her code:
foreach i in A B C D E F G H I J K L N P Q R S T U V W X Y Z {
bys id: egen nof`i'=sum(level=="`i'")}

Stata: Create id by group

Sunday, April 22, 2012

When doing your data analysis, sometimes you will encounter the following situation: in your dataset, everyone has an unique id. However, their IDs are long and each participant has multiple record (or the dataset is in a long format).

To visualize your data, you need to create a new ID for each individual regardless of how many records each person has. For example, the first person has three records, and we would like to assign a new ID 1 for the first person, and the second person would be 2.

Though it sounds difficult and tedious, it is not difficult to do so.  

egen id = group(oldid)

Just one line and your problem will be solved.

Reference: http://www.stata.com/support/faqs/data/group.html